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Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively.
`sqrt2 , 1/3`
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Solution
`sqrt2, 1/3`
Let the polynomial be ax2 + bx + c, and its zeroes be α and ß
Given α + ß = `sqrt2` = `(-b)/a`
αß = `1/3 = c/a`
If a = 3, then b = `sqrt2` and c = 1/3
Therefore, the quadratic polynomial is 3x2 - `3sqrt2` x +1.
Concept: Relationship Between Zeroes and Coefficients of a Polynomial
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