Maharashtra State BoardHSC Arts 12th Board Exam
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Find the Probability Distribution Of Number of Heads in Two Tosses of a Coin - Mathematics and Statistics

Sum

Find the probability distribution of number of heads in two tosses of a coin.

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Solution

When one coin is tossed twice, the sample space is

{HH, HT, TH, TT}

Let X represent the number of heads s in two tosses of a coin.

∴ X (HH) = 2, X (HT) = 1, X (TH) = 1, X (TT) = 0

Therefore, X can take the value of 0, 1, or 2.

It is known that,

P(HH) = P(HT) = P(TH) = P(TT) = `1/4`

P(X = 0) = P(TT) = `1/4`

P(X = 1) = P(HT) + P(TH) = `1/4 +1/4 = 1/2`

P(X = 2) = P(HH) = `1/4`

Thus, the required probability distribution is as follows.

X 0 1 2
P(X) `1/4` `1/2` `1/4`
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APPEARS IN

NCERT Class 12 Maths
Chapter 13 Probability
Q 4.1 | Page 570
Balbharati Mathematics and Statistics 2 (Arts and Science) 12th Standard HSC Maharashtra State Board
Chapter 7 Probability Distributions
Exercise 7.1 | Q 4.1 | Page 232
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