# Find the Points on the Y-axis Which is Equidistant Form the Points A(6,5) and B(- 4,3) - Mathematics

Find the points on the y-axis which is equidistant form the points A(6,5)  and B(- 4,3)

#### Solution

Let P (0, y) be a point on the y-axis. Then as per the question, we have

AP=BP

⇒ sqrt((0-6)^2 +(y-5)^2) = sqrt((0+4)^2 +(y-3)^2)

⇒sqrt((6)^2 +(y-5)^2) = sqrt((4)^2 +(y-3)^2)

⇒ (6)^2 +(y-5)^2 = (4)^2 +(y-3)^2              (Squaring both sides)

⇒ 36+y^2 - 10y +25 = 16+y^2-6y +9

⇒4y = 36

⇒y = 9

Hence, the point on the y-axis is ( 0,9) .

Concept: Coordinate Geometry
Is there an error in this question or solution?

#### APPEARS IN

RS Aggarwal Secondary School Class 10 Maths
Chapter 16 Coordinate Geomentry
Q 10