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Find the Points of Trisection of the Line Segment Joining the Points: (3, -2) and (-3, -4) - Mathematics

Find the points of trisection of the line segment joining the points:

(3, -2) and (-3, -4)

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Solution

The coordinates of a point which divided two points `(x_1,y_1)` and `(x_2, y_2)` internally in the ratio m:n is given by the formula,

`(x,y) = ((mx_2 + nx_1)/(m + n), (my_2 + ny_1)/(m + n))`

The points of trisection of a line are the points which divide the line into the ratio 1: 2.

Here we are asked to find the points of trisection of the line segment joining the points A(3,−2) and B(−3,−4).

So we need to find the points which divide the line joining these two points in the ratio 1: 2 and 2: 1.

Let P(x, y) be the point which divides the line joining ‘AB’ in the ratio 1: 2.

(x,y) = `(((1(3) + 2(-3))/(1 + 2)), ((1(-2) + 2(-4))/(1 + 2))`

`(e, d) = (-1, -10/3)`

Therefore the points of trisection of the line joining the given points are `(1, 8/3) and (-1, -10/3)`

  Is there an error in this question or solution?
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APPEARS IN

RD Sharma Class 10 Maths
Chapter 6 Co-Ordinate Geometry
Exercise 6.3 | Q 2.2 | Page 28
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