# Find the Point on the A-axis Which is Equidistant from the Points (2, -5) and (-2, 9). - Mathematics

Find the point on the a-axis which is equidistant from the points (2, -5) and (-2, 9).

#### Solution

Let (x, 0) be the point on the x axis. Then as per the question, we have

⇒ sqrt((x-2)^2 +(0+5)^2) = sqrt((x+2)^2 + (0-9)^2)

⇒sqrt((x-2)^2 +(5)^2) = sqrt((x+2)^2+(-9)^2)

⇒ (x-2)^2 + (5)^2 = (x+2)^2 +(-9)^2        (Squaring both sides)

⇒ x^2 -4x +4+25=x^2 +4x+4+81

⇒ 8x = 25-81

⇒x = -56/8=-7

Hence, the point on the x-axis is (- 7 ,0 ).

Concept: Coordinate Geometry
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#### APPEARS IN

RS Aggarwal Secondary School Class 10 Maths
Chapter 16 Coordinate Geomentry
Q 8