Question

Find p(0), p(1) and p(2) for the following polynomials:-

p(y) = y² – y + 1

Answer 1

p(y) = y² − y + 1

 

p(0) = (0)² − (0) + 1 = 1

p(1) = (1)² − (1) + 1 = 1

p(2) = (2)² − (2) + 1 = 3