Short Note
Find the number of degrees in each exterior exterior angle of a regular pentagon.
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Solution
\[\text{ Each exterior angle } = \left( \frac{360}{n} \right)^° \]
\[ \text{ For a regular pentagon, } n = 5 . \]
\[ \therefore\text{ Exterior angle } = \left( \frac{360}{5} \right)^° = 72° \]
Is there an error in this question or solution?
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