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Find: the Ninth Term of the G.P. 1, 4, 16, 64, ... - Mathematics

Find:
the ninth term of the G.P. 1, 4, 16, 64, ...

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Solution

Here,

\[\text { First term, } a = 1 \]

\[\text { Common ratio }, r = \frac{a_2}{a_1} = \frac{4}{1} = 4\]

\[ \therefore 9th\text {  term } = a_9 = a r^{(9 - 1)} = 1(4 )^8 = 4^8 = 65536\]

\[\text { Thus, the 9th term of the given GP is } 65536 .\]

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APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 20 Geometric Progression
Exercise 20.1 | Q 3.1 | Page 10
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