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Find the Next Three Terms of the Series: 2/27, 2/9, 2/3,.............. - Mathematics

Sum

Find the next three terms of the series:
`2/27, 2/9, 2/3,..............`

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Solution

Given sequence: `2/27, 2/9, 2/3,..............`
Now,

`(2/9)/(2/27)=3, (2/3)/(2/9)=3`

Since `(2/9)/(2/27) = (2/3)/(2/9)`=..........=3, the given sequence is a G.P. with first term, a = `2/27` and common ratio, r = 3.

Now, tn = arn-1

∴ Next three terms:

4th term =`2/27xx(3)^3=2/27xx27=2`

5th term =`2/27xx(3)^4=2/27xx27xx3=6`

6th term =`2/27xx(3)^5=2/27xx27xx9=18`

Concept: Geometric Progression - Finding Sum of Their First ‘N’ Terms
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APPEARS IN

Selina Concise Maths Class 10 ICSE
Chapter 11 Geometric Progression
Exercise 11 (A) | Q 11 | Page 152
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