# Find the Next Three Terms of the Series: 2/27, 2/9, 2/3,.............. - Mathematics

Sum

Find the next three terms of the series:
2/27, 2/9, 2/3,..............

#### Solution

Given sequence: 2/27, 2/9, 2/3,..............
Now,

(2/9)/(2/27)=3, (2/3)/(2/9)=3

Since (2/9)/(2/27) = (2/3)/(2/9)=..........=3, the given sequence is a G.P. with first term, a = 2/27 and common ratio, r = 3.

Now, tn = arn-1

∴ Next three terms:

4th term =2/27xx(3)^3=2/27xx27=2

5th term =2/27xx(3)^4=2/27xx27xx3=6

6th term =2/27xx(3)^5=2/27xx27xx9=18

Concept: Geometric Progression - Finding Sum of Their First ‘N’ Terms
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#### APPEARS IN

Selina Concise Maths Class 10 ICSE
Chapter 11 Geometric Progression
Exercise 11 (A) | Q 11 | Page 152