Find the maximum frequency of X-rays produced by 30 kV electrons.

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#### Solution

Potential of the electrons, *V* = 30 kV = 3 × 10^{4} V

Hence, energy of the electrons, *E *= 3 × 10^{4} eV

Where,

*e* = Charge on an electron = 1.6 × 10^{−19} C

**)**Maximum frequency produced by the X-rays = *ν*

The energy of the electrons is given by the relation:

*E *= *h**ν*

Where,

*h* = Planck’s constant = 6.626 × 10^{−34} Js

`:. v = E/h`

`= (1.6 xx 10^(-19) xx 3 xx 10^4)/(6.626 xx 10^(-34)) = 7.24 xx 10^18 Hz`

Concept: Electron Emission

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