Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
Advertisement Remove all ads

Find the Loss in the Mass of 1 Mole of an Ideal Monatomic Gas Kept in a Rigid Container as It Cools Down by 100°C. the Gas Constant R = 8.3 J K−1 Mol−1. - Physics


Find the loss in the mass of 1 mole of an ideal monatomic gas kept in a rigid container as it cools down by 100°C. The gas constant R = 8.3 J K−1 mol−1.

Advertisement Remove all ads


Given: Number of moles of gas, n = 1

Change in temperature, ∆T = 10°C

Energy possessed by a mono atomic gas,

\[E = \frac{3}{2}nRdT\]


\[R = 8.3 J/mol -K\]

This decrease in energy causes loss in mass of the gas. Thus,

Loss in mass, \[∆ m = \frac{Q}{c^2}\]

\[\Rightarrow ∆ m = \frac{1 . 5 \times 8 . 3 \times 10}{c^2}\]
\[ = \frac{124 . 5}{9 \times {10}^{16}} = 1 . 38 \times {10}^{- 15} kg\]

Concept: Energy and Momentum
  Is there an error in this question or solution?
Advertisement Remove all ads


HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 25 The Special Theory of Relativity
Q 19 | Page 458
Advertisement Remove all ads
Advertisement Remove all ads

View all notifications

      Forgot password?
View in app×