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Find the Lcm and Hcf of the Following Pairs of Integers and Verify that Lcm × Hcf = Product of the Integers: 26 and 91 - Mathematics

Numerical

Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = Product of the integers:

 26 and 91

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Solution

TO FIND: LCM and HCF of following pairs of integers 

TO VERIFY: L.C.M x H.C.F = product of the numbers

(i) 26 and 91

Let us first find the factors of 26 and 91

26=2 x 13

91= 7 x 13 

L.C.M of 26 and 91=2 x 7 x 13

L.C.M of 26 and 91 = 182

H.C.F of 26 and 91 = 13

We know that,

\[\text{L . C . M} \times \text{H . C . F} = \text{First number} \times \text{Second number}\]
\[ \Rightarrow 182 \times 13 = 26 \times 91\]
\[ \Rightarrow 2366 = 2366\]

Hence verified

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APPEARS IN

RD Sharma Class 10 Maths
Chapter 1 Real Numbers
Exercise 1.4 | Q 1.1 | Page 39
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