Find the intercepts cut off by the plane 2x + y – z = 5.

Find the sum of the intercepts cut off by the plane \[2x + y - z = 5,\]on the coordinate axes.

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#### Solution

2x + y – z = 5 ...(1)

Dividing both sides of equation (1) by 5, we obtain

Thus, the intercepts cut off by the plane are `5/2, 5 and -5`

∴ Required sum of intercepts = \[\frac{5}{2} + 5 + \left( - 5 \right) = \frac{5}{2}\] .

Is there an error in this question or solution?

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