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Find the integrals of the functions `1/(sin xcos^3 x)`
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Solution
1sinxcos3x=sin2x+cos2xsinxcos3x=sinxcos3x+1sinxcosx
⇒1sinxcos3x=tanxsec2x+1cos2xsinxcosxcos2x
=tanxsec2x+sec2xtanx
Concept: Integration Using Trigonometric Identities
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