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Find the Greatest Number Which Divides 285 and 1249 Leaving Remainders 9 and 7 Respectively. - CBSE Class 10 - Mathematics

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Question

Find the greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively.

Solution

The require number when divides 285 and 1249, leaves remainder 9 and 7, this means 285 – 9 = 276 and 1249 – 7 = 1242 are completely divisible by the number

∴ The required number = HCF of 276 and 1242

By applying Euclid’s division lemma

1242 = 276 × 4 + 138

276 = 138 × 2 + 0

∴ HCF = 138

Hence remainder is = 0

Hence required number is 138

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APPEARS IN

 RD Sharma Solution for 10 Mathematics (2018 to Current)
Chapter 1: Real Numbers
Ex. 1.20 | Q: 11 | Page no. 28

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Solution Find the Greatest Number Which Divides 285 and 1249 Leaving Remainders 9 and 7 Respectively. Concept: Euclid’s Division Lemma.
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