Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Find the general solution of the equation `4cos^2x=1`
Advertisement Remove all ads
Solution
Given:
`4cos^2x=1`
`cos^2x=1/4`
`cos^2x=cos^2(pi/3)`
`["Using " cos^2x=cos^2alpha => x=npi+-alpha]`
`x=npi+-pi/3" where " n in Z`
Concept: Trigonometric Functions - General Solution of Trigonometric Equation of the Type
Is there an error in this question or solution?
