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Find the Fundamental, First Overtone and Second Overtone Frequencies of an Open Organ Pipe of Length 20 Cm. Speed of Sound in Air is 340 Ms−1. - Physics

Sum

Find the fundamental, first overtone and second overtone frequencies of an open organ pipe of length 20 cm. Speed of sound in air is 340 ms−1.

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Solution

Given:
Speed of sound in air v = 340 m/s
Length of open organ pipe L = 20 cm = 20 × 10−2 m
Fundamental frequency \[\left( f \right)\] of an open organ pipe :

\[f = \left( \frac{v}{2L} \right) = \frac{340}{2 \times 20 \times {10}^{- 2}}=850\text { Hz }\]

First overtone frequency \[\left( f_1 \right)\] : 

f1 = \[2f\]

\[\Rightarrow  f_1  = \left( \frac{2V}{2I} \right) = 2 \times 850 = 1700 \text{ Hz }\]

Second overtone frequency \[\left( f_2 \right)\] : 

\[f_2  = 3f\]\[ \Rightarrow  f_2  = 3\left( \frac{V}{2L} \right) = 3 \times 850 = 2550  \text { Hz }\]

Concept: Speed of Wave Motion
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APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 16 Sound Waves
Q 36 | Page 355
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