Answer 1

Given:
Depth of the stone from the water surface, h = 500 m
Area of the plane surface of the large stone, A = 2 m² 
Density of water, ρ_w = 10³ kgm^−3
​Force (F) is given by 

\[F = P \times A = \left( h \rho_w \times g \right)A \left( P = \text{ Pressure }\right)\]

\[ \Rightarrow \text{ F }= \left( 500 \times {10}^3 \times 10 \right) \times 2\]

\[ = {10}^7 \text{ N/ m}^2\]

The force does not depend on the orientation of the rock when the surface area of the stone remains the same.