Find the following squares by suing the identities.
`(2/3 m + 3/4 n)^2`
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Solution
`(2/3 m + 3/4 n)^2` = `(2/3 m)^2 + 2(2/3 m)(3/2 n)+ (3/2 n)^2` [(a + b)2 = a2 + 2ab + b2]
= `4/9 m^2 + 2mn + 9/4 n^2`
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