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Solution
(i)
`1/C_(eqv)=1/2+1/6+1/2=7/6`
`C_(eqv)=6/7 μF`
(ii) `Q=C_(eqv)V`
`Q=6/7×7`
`Q=6 " μC"`
`E=1/2CV^2`
`E=1/2×6/7×(49)`
`E=21 J`
Concept: Capacitors and Capacitance
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