# Find the Equation of the Plane Which Contains the Line of Intersection of the Planes Vecrr.(Hati + 2hatj + 3hatk) - 4 = 0, Vecr.(2hati + Htj - Hatk) + 5, And Which is Perpendicular to the Plane Vecr.(5hati + 3hatj - 6hatk) + 8 = 0 - Mathematics

Find the equation of the plane which contains the line of intersection of the planes vecrr.(hati + 2hatj + 3hatk) - 4 = 0, vecr.(2hati + htj - hatk) + 5 = 0,  and which is perpendicular to the plane vecr.(5hati + 3hatj - 6hatk) + 8 = 0.

#### Solution

The equations of the given planes are

vecrr.(hati + 2hatj + 3hatk) - 4 = 0 ...(1)

vecr.(2hati + htj - hatk) + 5 = 0`  ...(2)

The equation of the plane passing through the line intersection of the plane given in equation (1) and equation (2) is

Is there an error in this question or solution?

#### APPEARS IN

NCERT Class 12 Maths
Chapter 11 Three Dimensional Geometry
Q 17 | Page 498