Find the equation of the plane which contains the line of intersection of the planes `vecrr.(hati + 2hatj + 3hatk) - 4 = 0, vecr.(2hati + htj - hatk) + 5 = 0`, and which is perpendicular to the plane `vecr.(5hati + 3hatj - 6hatk) + 8 = 0`.
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Solution
The equations of the given planes are
`vecrr.(hati + 2hatj + 3hatk) - 4 = 0` ...(1)
`vecr.(2hati + htj - hatk) + 5 = 0` ...(2)
The equation of the plane passing through the line intersection of the plane given in equation (1) and equation (2) is
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