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# Find the Equation of the Line Which Passes Through the Point (3, 4) and is Such that the Portion of It Intercepted Between the Axes is Divided by the Point in the Ratio 2:3. - Mathematics

Definition

Find the equation of the line which passes through the point (3, 4) and is such that the portion of it intercepted between the axes is divided by the point in the ratio 2:3.

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#### Solution

The equation of the line with intercepts a and b is $\frac{x}{a} + \frac{y}{b} = 1$ .Since the line meets the coordinate axes at A and B, the coordinates are A (a, 0) and (0, b).
Let the given point be P (3, 4).
Here,

$AP : BP = 2 : 3$

$\therefore 3 = \frac{2 \times 0 + 3 \times a}{2 + 3}, 4 = \frac{2 \times b + 3 \times 0}{2 + 3}$

$\Rightarrow 3a = 15, 2b = 20$

$\Rightarrow a = 5, b = 10$

Hence, the equation of the line is

$\frac{x}{5} + \frac{y}{10} = 1$

$\Rightarrow 2x + y = 10$

Concept: Straight Lines - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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#### APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 23 The straight lines
Exercise 23.6 | Q 8 | Page 47
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