Sum
Find the equation of the line through the points A(-1,3) and B(0,2). Hence, show that the pointA,B and C (1,1) are collinear.
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Solution
Slop of line AB=m=` (2-3)/(0-1(-1))=(-1)/1=-1`
Using the slope-point from, the equation of line Ab is given by
`y-y_1=m(x-x_1)`
i.e. `y-3=-1[x-(-1)]`
i.e.`y-3=-1(x+1)`
i.e.`y-3=-x-1`
i.e.` x+y=2`
Now, slope of line` BC=(1-2)/(1-0)=-1/1=-1`
Since, slope of line Ab= slope of line BC, Point A, B and C are collinear.
Concept: General Equation of a Line
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