# Find the equation of a line drawn perpendicular to the line x 4 + y 6 = 1 through the point where it meets the y-axis. - Mathematics

Find the equation of a line drawn perpendicular to the line $\frac{x}{4} + \frac{y}{6} = 1$ through the point where it meets the y-axis.

#### Solution

Let us find the intersection of the line $\frac{x}{4} + \frac{y}{6} = 1$ with y-axis.
At x = 0,

$0 + \frac{y}{6} = 1$

$\Rightarrow y = 6$

Thus, the given line intersects y-axis at (0, 6).
The line perpendicular to the line $\frac{x}{4} + \frac{y}{6} = 1$ is $\frac{x}{6} - \frac{y}{4} + \lambda = 0$

This line passes through (0, 6).

$0 - \frac{6}{4} + \lambda = 0$

$\Rightarrow \lambda = \frac{3}{2}$

Now, substituting the value of $\lambda$,we get:

$\frac{x}{6} - \frac{y}{4} + \frac{3}{2} = 0$

$\Rightarrow 2x - 3y + 18 = 0$

This is the equation of the required line.

Concept: Straight Lines - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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#### APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 23 The straight lines
Exercise 23.12 | Q 16 | Page 93