Find the equation of the circle with radius 5 whose centre lies on *x*-axis and passes through the point (2, 3).

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#### Solution

Let the equation of the required circle be (*x* – *h*)^{2} + (*y* – *k*)^{2} = *r*^{2}.

Since the radius of the circle is 5 and its centre lies on the *x*-axis, *k* = 0 and *r* = 5.

Now, the equation of the circle becomes (*x* – *h*)^{2} + *y*^{2} = 25.

It is given that the circle passes through point (2, 3).

Concept: Concept of Circle

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