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Find the Equation of the Circle with Radius 5 Whose Centre Lies on X-axis and Passes Through the Point (2, 3). - Mathematics

Find the equation of the circle with radius 5 whose centre lies on x-axis and passes through the point (2, 3).

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Solution

Let the equation of the required circle be (x – h)2 + (y – k)2 = r2.

Since the radius of the circle is 5 and its centre lies on the x-axis, k = 0 and r = 5.

Now, the equation of the circle becomes (x – h)2 + y2 = 25.

It is given that the circle passes through point (2, 3).

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APPEARS IN

NCERT Class 11 Mathematics Textbook
Chapter 11 Conic Sections
Q 12 | Page 241
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