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Find the Equation of a Circle with Centre (2, 2) and Passes Through the Point (4, 5). - Mathematics

Find the equation of a circle with centre (2, 2) and passes through the point (4, 5).

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Solution

The centre of the circle is given as (hk) = (2, 2).

Since the circle passes through point (4, 5), the radius (r) of the circle is the distance between the points (2, 2) and (4, 5).

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APPEARS IN

NCERT Class 11 Mathematics Textbook
Chapter 11 Conic Sections
Q 14 | Page 241
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