Find energy of each of the photons which correspond to light of frequency 3 × 1015 Hz. - Chemistry

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Numerical

Find energy of each of the photons which correspond to light of frequency 3 × 1015 Hz.

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Solution

Energy (E) of a photon is given by the expression,

E = hv

Where,

h = Planck’s constant = 6.626 × 10-34 Js

ν = frequency of light = 3 × 1015 Hz

Substituting the values in the given expression of E:

E = (6.626 × 10-34) (3 × 1015)

E = 1.988 × 10-18 J

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Chapter 2: Structure of Atom - EXERCISES [Page 69]

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NCERT Chemistry Part 1 and 2 Class 11
Chapter 2 Structure of Atom
EXERCISES | Q 2.6 - (i) | Page 69

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