Find energy of each of the photons which correspond to light of frequency 3× 1015 Hz.
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Solution
Energy (E) of a photon is given by the expression,
`E=hv`
Where,
h = Planck’s constant = 6.626 × 10–34 Js
ν = frequency of light = 3 × 1015 Hz
Substituting the values in the given expression of E:
E = (6.626 × 10–34) (3 × 1015)
E = 1.988 × 10–18 J
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