Find the Empirical Formula and the Molecular Formula of an Organic Compound from the Data Given Below : C = 75.92%, H = 6.32% and N = 17.76% the Vapour Density of the Compound is 39.5. - Chemistry

Sum

Find the empirical formula and the molecular formula of an organic compound from the data given below :
C = 75.92%, H = 6.32% and N = 17.76%
The vapour density of the compound is 39.5.
[C = 12, H = 1, N = 14]

Solution

 Element % C 75.92 75.92/12 = 6.32/1.26  = 5 H 6.32 6.32/1 = 6.32/1.26 = 5 N 17.76 17.76/14 = 1.26/1.26 = 1

Empirical formula ; - C5H5N

Molecular weight = 2 ×  Vapour Density
= 2 × 39.5

= 79
Empirical formula weight = C × 5 + H × 5 + N × 1
= 12 × 5 + 1 × 5 + 14 × 1
= 60 + 5 + 14
= 79

n = "Molecular weight"/("Empirical"  "formula"  "weight" )
∴ Molecular formula = Empirical formula = C5H5N

Concept: Deduction of Simple (Empirical) and Molecular Formula from the Percentage Composition of a Compound
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