Maharashtra State BoardHSC Commerce 11th
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Find dydxify=(x+1)2 - Mathematics and Statistics

Sum

Find `dy/dx if y=(sqrtx+1)^2`

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Solution

`y=(sqrtx+1)^2`

∴ `y = x + 2 sqrtx + 1`
Differentiating w.r.t. x, we get

`dy/dx=d/dx(x+2sqrtx+1)`

=`d/dx(x)+2d/dx(sqrtx)+d/dx(1)`

= `1+2(1/(2sqrtx))+0`

`dy/dx=1+1/sqrtx`

Concept: Rules of Differentiation (Without Proof)
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APPEARS IN

Balbharati Mathematics and Statistics 1 (Commerce) 11th Standard Maharashtra State Board
Chapter 9 Differentiation
Miscellaneous Exercise 9 | Q II. (2) | Page 123
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