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Sum

Find `"dy"/"dx"` if, y = log(log x)

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#### Solution

y = log(log x)

Differentiating both sides w.r.t.x, we get

`"dy"/"dx" = "d"/"dx"` [log (log x)]

`= 1/(log "x") * "d"/"dx" (log "x")`

`= 1/(log "x") * 1/"x"`

∴ `"dy"/"dx" = 1/("x" * log "x")`

Is there an error in this question or solution?