Question

Find `"dy"/"dx"` if, y = log(log x)

Answer 1

y = log(log x)

Differentiating both sides w.r.t.x, we get

`"dy"/"dx" = "d"/"dx"` [log (log x)]

`= 1/(log "x") * "d"/"dx" (log "x")`

`= 1/(log "x") * 1/"x"`

∴ `"dy"/"dx" = 1/("x" * log "x")`