Find `dy/dx`
`y = tan^(-1) ((3x -x^3)/(1 - 3x^2)), - 1/sqrt3 < x < 1/sqrt3`
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Solution
The given relationship is y = `y = tan^(-1) ((3x -x^3)/(1 - 3x^2))`
y = `y = tan^(-1) ((3x -x^3)/(1 - 3x^2))`
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