Sum
Find the distance between P (x1, y1) and Q (x2, y2) when (i) PQ is parallel to the y-axis (ii) PQ is parallel to the x-axis.
Advertisement Remove all ads
Solution
The given points are \[P\left( x_1 , y_1 \right)\text{ and }Q\left( x_2 , y_2 \right)\]
Distance between P and Q is: \[PQ = \sqrt{\left( x_1 - x_2 \right)^2 + \left( y_1 - y_2 \right)^2}\]
(i) When PQ is parallel to the y-axis: In this case, \[x_1 = x_2\]
\[\therefore PQ = \sqrt{\left( x_1 - x_1 \right)^2 + \left( y_1 - y_2 \right)^2} = \left| y_1 - y_2 \right|\]
(ii) When PQ is parallel to the x-axis:
In this case, \[y_1 = y_2\]
\[\therefore PQ = \sqrt{\left( x_1 - x_2 \right)^2 + \left( y_1 - y_1 \right)^2} = \left| x_1 - x_2 \right|\]
Concept: Brief Review of Cartesian System of Rectanglar Co-ordinates
Is there an error in this question or solution?
Advertisement Remove all ads
APPEARS IN
Advertisement Remove all ads
Advertisement Remove all ads