Question

Find the direction cosines of the line 

`(x+2)/2=(2y-5)/3; z=-1`

Answer 1

Equation of line is  `(x+2)/2=(2y-5)/3;z=-1`

`(x+2)/2=(y-5/2)/(3/2)=(z+1)/1`

Direction ratios of the line are 2, 3/2, 1.

∴Direction cosines of the line are

`2/(sqrt(4+(9/4)+1)),(3/2)/sqrt(4+9/4+1),1/sqrt(4+9/4+1)`

`i.e 2/(1/2sqrt(29/4)),(3/2)/(1/2sqrt(29/4)),1/(1/2sqrt(29/4))  `

`4/sqrt(29),3/sqrt(29),2/sqrt(29)`