Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 11

Find the Dimensions of Magnetic Field B. the Relevant Equation Are F = Q E , F = Q V B , and B = μ 0 I 2 π a ; Where F is Force, Q is Charge, V is Speed, I is Current, and a is Distance. - Physics

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Sum

Find the dimensions of magnetic field B.
The relevant equation are \[F = qE, F = qvB, \text{ and }B = \frac{\mu_0 I}{2 \pi a};\]

where F is force, q is charge, v is speed, I is current, and a is distance.

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Solution

Magnetic field,
\[B = \frac{F}{qv}\]
\[\text{ Here, } \left[ F \right] = {\left[ {MLT}^{- 2} \right]}, \left[ q \right] = {\left[ AT \right]} \text{ and } \left[ v \right] = {\left[ {LT}^{- 1} \right]} \]
\[\text{ So, dimension of magnetic field }, [B] = \frac{\left[ {MLT}^{- 2} \right]}{\left[ AT \right] \left[ {LT}^{- 1} \right]} = \left[ M L^0 T^{- 2} A^{- 1} \right]\]

Concept: What is Physics?
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APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 1
Chapter 1 Introduction to Physics
Exercise | Q 3.2 | Page 9
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