Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 11

# Find the Dimensions of Electric Field E. the Relevant Equation Are F = Q E , F = Q V B , and B = μ 0 I 2 π a ; Where F is Force, Q is Charge, V is Speed, I is Current, and a is Distance. - Physics

Sum

Find the dimensions of electric field E.

The relevant equations are $F = qE, F = qvB, \text{ and }B = \frac{\mu_0 I}{2 \pi a};$
where F is force, q is charge, v is speed, I is current, and a is distance.

#### Solution

Electric field is defined as electric force per unit charge.
i.e., $E = \frac{F}{q}$
$\text{ Also,} \left[ F \right] = {\left[ {MLT}^{- 2} \right]} \text{ and } \left[ q \right] ={\left[ AT \right]}$
$\text{ So, dimension of electric field }, [E] = \left[ {MLT}^{- 3} A^{- 1} \right]$

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#### APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 1 Introduction to Physics
Exercise | Q 3.1 | Page 10