Find the Diagonal of a Rectangle Whose Length is 16 Cm and Area is 192 Sq.Cm. - Geometry Mathematics 2


Find the diagonal of a rectangle whose length is 16 cm and area is 192 ?



It is given that, area of rectangle is 192

\[\text{Area} = \text{Length} \times \text{Breadth}\]
\[ \Rightarrow 192 = 16 \times \text{BC}\]
\[ \Rightarrow \text{BC} = \frac{192}{16}\]
\[ \Rightarrow \text{BC} = 12 \text{cm} . . . \left( 1 \right)\]

According to Pythagoras theorem,


\[{\text{AB}}^2 + {\text{BC}}^2 = {\text{AC}}^2 \]
\[ \Rightarrow \left( 16 \right)^2 + \left( 12 \right)^2 = {\text{AC}}^2 \]
\[ \Rightarrow 256 + 144 = {\text{AC}}^2 \]
\[ \Rightarrow {\text{AC}}^2 = 400\]
\[ \Rightarrow \text{AC} = 20 \text{cm}\]

Hence, the length of a diagonal of the rectangle is 20 cm.

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Chapter 2: Pythagoras Theorem - Problem Set 2 [Page 44]


Balbharati Mathematics 2 Geometry 10th Standard SSC Maharashtra State Board
Chapter 2 Pythagoras Theorem
Problem Set 2 | Q 4 | Page 44


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