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Numerical

Find cylindrical co-ordinates of a point (3𝒊̅ + 4𝒋̅ + 𝒌̅)

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#### Solution

The point is (3,4,1)

`r =sqrt(x^2+y^2)`

`=sqrt(3^2+4^2)`

= 5

`θ = tan^-1(y/x)`

`= tan^-1(4/3)`

= 53.13^{o}

= 0.2952𝝅

z = z = 1

Point in cylindrical system is (5,0.2952𝝅,𝟏)

Concept: Cylindrical and Spherical Coordinate System

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