# Find Cylindrical Co-ordinates of a Point (3𝒊̅ + 4𝒋̅ + 𝒌̅) - Applied Physics 2

Numerical

Find cylindrical co-ordinates of a point (3𝒊̅ + 4𝒋̅ + 𝒌̅)

#### Solution

The point is (3,4,1)
r =sqrt(x^2+y^2)
=sqrt(3^2+4^2)
= 5
θ = tan^-1(y/x)
= tan^-1(4/3)
= 53.13o

= 0.2952𝝅
z = z = 1

Point in cylindrical system is (5,0.2952𝝅,𝟏)

Concept: Cylindrical and Spherical Coordinate System
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