#### Question

Find a cubic polynomial with the sum, sum of the product of its zeroes taken two at a time, and the product of its zeroes as 2, − 7, − 14 respectively

#### Solution

Let the polynomial be ax^{3} + bx^{2 }+ cx* + d *and the zeroes be α, β and γ

Then, α + β + γ = `(2)/1 = (-b)/a`

αβ + βγ + γα = `(-7)/1 = c/a`

αβγ = `(-14)/1 = (-d)/a`

∴ a = 1, b = -2, c = -7 and d = 14

Hence, the polynomial is x^{3} - 2x^{2 }- 7x + 14

Is there an error in this question or solution?

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Find a cubic polynomial with the sum, sum of the product of its zeroes taken two at a time, and the product of its zeroes as 2, − 7, − 14 respectively Concept: Relationship Between Zeroes and Coefficients of a Polynomial.

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