Advertisement Remove all ads

Find correlation coefficient between x and y series for the following data.n = 15, x¯ = 25, y¯ = 18, σx = 3.01, σy = 3.03, ∑(xi-x¯)(yi-y¯) = 122 - Mathematics and Statistics

Advertisement Remove all ads
Advertisement Remove all ads
Sum

Find correlation coefficient between x and y series for the following data.
n = 15, `bar"x"` = 25, `bar"y"` = 18, σx = 3.01, σy = 3.03, `sum("x"_"i" - bar"x") ("y"_"i" - bar"y")` = 122

Advertisement Remove all ads

Solution

here, n = 15, `bar"x"` = 25, `bar"y"` = 18, σx = 3.01, σy = 3.03, and `sum("x"_"i" - bar"x") ("y"_"i" - bar"y")` = 122

Since, Cov (x, y) = `1/"n" sum_("i"=1)^"n"("x"_"i"-bar"x")("y"_"i"-bar"y")`

∴ Cov (x, y) = `1/15xx122`

= 8.13
Since, r  = `("Cov"("x","y"))/(sigma_"x"sigma_"y")`

∴ = `8.13/(3.01 xx 3.03)`

= `8.13/9.1203`
∴ r = 0.89

Concept: Concept of Correlation Coefficient
  Is there an error in this question or solution?
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×