# Find correlation coefficient between x and y series for the following data.n = 15, x¯ = 25, y¯ = 18, σx = 3.01, σy = 3.03, ∑(xi-x¯)(yi-y¯) = 122 - Mathematics and Statistics

Sum

Find correlation coefficient between x and y series for the following data.
n = 15, bar"x" = 25, bar"y" = 18, σx = 3.01, σy = 3.03, sum("x"_"i" - bar"x") ("y"_"i" - bar"y") = 122

#### Solution

here, n = 15, bar"x" = 25, bar"y" = 18, σx = 3.01, σy = 3.03, and sum("x"_"i" - bar"x") ("y"_"i" - bar"y") = 122

Since, Cov (x, y) = 1/"n" sum_("i"=1)^"n"("x"_"i"-bar"x")("y"_"i"-bar"y")

∴ Cov (x, y) = 1/15xx122

= 8.13
Since, r  = ("Cov"("x","y"))/(sigma_"x"sigma_"y")

∴ = 8.13/(3.01 xx 3.03)

= 8.13/9.1203
∴ r = 0.89

Concept: Concept of Correlation Coefficient
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