#### Question

Find and correct the errors in the statement: (*y* − 3)^{2} = *y*^{2} − 9

#### Solution

L.H.S = (*y* − 3)^{2} = (*y*)^{2} − 2(*y*)(3) + (3)^{2} [(*a* − *b*)^{2} = *a*^{2} − 2*ab* + *b*^{2}]

= *y*^{2} − 6*y* + 9 ≠ R.H.S

The correct statement is (*y* − 3)^{2} = *y*^{2} − 6*y* + 9

Is there an error in this question or solution?

Solution Find and Correct the Errors in the Statement: (Y − 3)Square2 = Ysquare2 − 9 Concept: Concept of Find the Error.