Find the Coordinates of the Points of Trisection of the Line Segment Joining (4, -1) and (-2, -3). - Mathematics

Sum

Find the coordinates of the points of trisection of the line segment joining (4, -1) and (-2, -3).

Solution

Let P (x1, y1) and Q (x2, y2) are the points of trisection of the line segment joining the given points i.e., AP = PQ = QB

Therefore, point P divides AB internally in the ratio 1:2.

∴ x = (m_1x_2 + m_2x_1)/(m_1 + m_2),   y = (m_1y_2 + m_2y_1)/(m_1 + m_2)

x_1= (1xx(-2)+2xx4)/(1+2), y_1 = (1xx(-3)+2xx(-1))/(1+2)

x_1 = (-2+8)/3=6/3=2, y_1 = (-3-2)/3 = (-5)/3

Therefore P(x1,y1) = (2, -5/3)

Point Q divides AB internally in the ratio 2:1.

∴ x = (m_1x_2 + m_2x_1)/(m_1 + m_2),   y = (m_1y_2 + m_2y_1)/(m_1 + m_2)

x_2=(2xx(-2)+1xx4)/(2+1), y_2=(2xx(-3)+1xx(-1))/(2+1)

x_2 = (-4+4)/3 = 0, y_2= (-6-1)/3 = (-7)/3

Q(x_2, y_2) = (0, -7/3)

Concept: Section Formula
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Chapter 7: Coordinate Geometry - Exercise 7.2 [Page 167]

APPEARS IN

NCERT Mathematics Class 10
Chapter 7 Coordinate Geometry
Exercise 7.2 | Q 2 | Page 167

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