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Sum

Find the coordinates of a point A, where AB is the diameter of circle whose centre is (2, − 3) and B is (1, 4)

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#### Solution

Let the centre of the circle be O.

Since AB is the diameter so, O is the midpoint of AB.

Thus, using the section formula,

`("a" +1)/2 = 2`

⇒ a = 4 - 1 = 3

and

`("b" + 4)/2 = -3`

⇒ b = - 10

So, the coordinate of point A is (3 , -10)

Concept: Section Formula

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