#### Question

Find the charge on the capacitor as shown in the circuit.

#### Solution

Total current *I* through the circuit is given by

\[I = \frac{V}{R}\]

Here,

*V*= 2 V*R*= (10+20) Ω = 30 Ω\[\therefore I = \frac{2}{30} = \frac{1}{15} A\]

Voltage across 10 Ω resistor =\[I(10) = \frac{10}{15} = \frac{2}{3} V\]

∴ Charge on the capacitor is given by \[Q = CV = \left( 6 \times {10}^{- 6} \right)\left( \frac{2}{3} \right) = 4 \mu C\]

Is there an error in this question or solution?

Solution Find the Charge on the Capacitor as Shown in the Circuit. Concept: Energy Stored in a Capacitor.