CBSE (Commerce) Class 12CBSE
Share
Notifications

View all notifications

Find the Cartesian Equation of the Line Which Passes Through the Point (−2, 4, −5) and Parallel to the Line Given by `(X+3)/3 = (Y-4)/5 = (Z+8)/6` - CBSE (Commerce) Class 12 - Mathematics

Login
Create free account


      Forgot password?

Question

Find the Cartesian equation of the line which passes through the point (−2, 4, −5) and parallel to the line given by `(x+3)/3 = (y-4)/5 = ("z"+8)/6`

Solution

It is given that the line passes through the point (−2, 4, −5) and is parallel to

`(x+3)/3 = (y-4)/5 = (z+8)/6`

The direction ratios of the line, 

`(x+3)/3 = (y-4)/5 = (z+8)/6` are 3, 5, and 6.

The required line is parallel to `(x+3)/3 = (y-4)/5 = (z+8)/6`

Therefore, its direction ratios are 3k, 5k, and 6k, where k ≠ 0

It is known that the equation of the line through the point (x1y1z1) and with direction ratios, abc, is given by `(x-x_1)/a = (y-y_1)/b = (z-z_1)/c`

Therefore the equation of the required line is 

 

 

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 12 (2018 to Current)
Chapter 11: Three Dimensional Geometry
Q: 6 | Page no. 477
Solution Find the Cartesian Equation of the Line Which Passes Through the Point (−2, 4, −5) and Parallel to the Line Given by `(X+3)/3 = (Y-4)/5 = (Z+8)/6` Concept: Equation of a Line in Space.
S
View in app×