Find the Cartesian equation of the following planes:

`vecr.(hati + hatj-hatk) = 2`

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#### Solution

It is given that equation of the plane is

`vecr.(hati + hatj-hatk) = 2`

For any arbitrary point P (*x*, *y*, *z*) on the plane, position vector `vecr`is given by,

`vecr = xhati +yhatj-zhatk`

Substituting the value of `vecr` in equation (1), we obtain

`(xhati + yhatj - zhatk).(hati + hatj - hatk) = 2`

=> x + y - z = 2

This is the Cartesian equation of the plane.

Concept: Vector and Cartesian Equation of a Plane

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