# Find the Area of a Triangle Whose Vertices Are (6,3), (-3,5) and (4,2) - Mathematics

Find the area of a triangle whose vertices are

(6,3), (-3,5) and (4,2)

#### Solution

We know area of triangle formed by three points (x1y1) , (x2y2), and (x3y3)is given by triangle=1/2 [x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]

The vertices are given as (6, 3), (−3, 5), (4, −2).

triangle=1/2[6(5+2)-3(-2-3)+4(3-5)]

=1/2 [6xx7-3xx(-5)+4xx(-2)]

=1/2[42+15-8]

49/2 sq units

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#### APPEARS IN

RD Sharma Class 10 Maths
Chapter 6 Co-Ordinate Geometry
Exercise 6.5 | Q 1.1 | Page 53