# Find the Area of a Triangle Whose Sides Are 9 Cm, 12 Cm and 15 Cm ? - Mathematics

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Find the area of a triangle whose sides are 9 cm, 12 cm and 15 cm ?

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#### Solution

The triangle whose sides are a = 9cm, b = 12 cm and c = 15 cm
The area of a triangle =sqrt(s(s-a)(s-b)(s-c))

Here 1s = semi-perimeter of a triangle
2s = a + b + c

s=(a+b+c)/2=(9+12+15)/2=(36)/2=18cm

∴ area of a triangle= sqrt(s(s-a)(s-b)(s-c))

=sqrt(18(18-9)(18-12)(18-15))=sqrt(18(9)(6)(3))

=sqrt(18cm xx3cmxx54cm^2) =54cm^2

Concept: Area of a Triangle
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#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 17 Heron’s Formula
Exercise 17.1 | Q 2 | Page 8
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