Find the Area of a Trapezium Whose Parallel Sides Are of Length 16 Dm and 22 Dm and Whose Height is 12 Dm. - Mathematics

Sum

Find the area of a trapezium whose parallel sides are of length 16 dm and 22 dm and whose height is 12 dm.

Solution

Given:
Lengths of the parallel sides are 16 dm and 22 dm.
And, height between the parallel sides is 12 dm.
Area of trapezium $\frac{1}{2}\times(\text{ Sum of the parallel sides })\times(\text{ Height })$
$= \frac{1}{2} \times (16 + 22) \times (12)$
${=228 dm}^2$
$= 228 \times dm\times dm$
$=228\times\frac{1}{10}m\times\frac{1}{10}m$
$= 2 . 28 m^2$

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APPEARS IN

RD Sharma Class 8 Maths
Chapter 20 Mensuration - I (Area of a Trapezium and a Polygon)
Exercise 20.2 | Q 3 | Page 22

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