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# Find the Area, in Square Metres, of the Trapezium Whose Bases and Altitude is as Under: Bases = 150 Cm and 30 Dm, Altitude = 9 Dm. - Mathematics

Course
ConceptArea of Trapezium

#### Question

Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 150 cm and 30 dm, altitude = 9 dm.

#### Solution

Given:
Bases:
$150 cm =\frac{150}{100}m = 1.5 m$
And, 30 dm $=\frac{30}{10}m = 3 m$
Altitude = 9 dm $=\frac{9}{10}m = 0.9 m$
Area of trapezium$=\frac{1}{2}\times(\text{ Sum of the bases })\times(\text{ Altitude })$
$= \frac{1}{2} \times (1 . 5 + 3) m \times (0 . 9) m$
$= 2 . 025 \times m\times m$
${=2.025 m}^2$

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#### APPEARS IN

RD Sharma Solution for Mathematics for Class 8 by R D Sharma (2019-2020 Session) (2017 to Current)
Chapter 20: Mensuration - I (Area of a Trapezium and a Polygon)
Ex. 20.2 | Q: 1.4 | Page no. 22

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Solution Find the Area, in Square Metres, of the Trapezium Whose Bases and Altitude is as Under: Bases = 150 Cm and 30 Dm, Altitude = 9 Dm. Concept: Area of Trapezium.
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